Не могу получить ссылку с xvideos

  • Автор темы DeltaKilo
  • Обновлено
  • 18, May 2024
  • #1
Видите ли, я рассматриваю этот код
 <?php
error_reporting(E_ERROR | E_PARSE);
function curl_Xvideos($url)
{
 $ch = @curl_init();
 curl_setopt($ch, CURLOPT_URL, $url);
 curl_setopt($ch, CURLOPT_COOKIEFILE, 'cookie.txt');
 $head[] = "Connection: keep-alive";
 $head[] = "Keep-Alive: 300";
 $head[] = "Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.7";
 $head[] = "Accept-Language: en-us,en;q=0.5";
 curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/5.0 (iPhone; U; CPU like Mac OS X; en) AppleWebKit/420.1 (KHTML, like Gecko) Version/3.0 Mobile/3B48b Safari/419.3');
 curl_setopt($ch, CURLOPT_HTTPHEADER, $head);
 curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
 curl_setopt($ch, CURLOPT_ENCODING , 'gzip, deflate');
 curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, FALSE);
 curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE);
 curl_setopt($ch, CURLOPT_TIMEOUT, 60);
 curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 60);
 curl_setopt($ch, CURLOPT_FOLLOWLOCATION, TRUE);
 curl_setopt($ch, CURLOPT_HTTPHEADER, array('Expect:'));
 $page = curl_exec($ch);
 curl_close($ch);
 return $page;

 $url = str_replace(' ', '', $url);
 if(!empty($url)):
 curl_setopt($curl = curl_init($url), CURLOPT_RETURNTRANSFER, 1);
 preg_match("/flv_url=(.+)url_bigthumb=([^&]+)/i", curl_exec($curl), $infos);
 curl_close($curl);
 header("Location: ".urldecode($infos[1]));
 endif;
}

function Xvideos($link) {
 $view_source = curl_Xvideos($link);
 $data = explode("new HTML5Player('html5video',", $view_source);
 $data = explode("[URL='https://lumtu.com/yti/bQaaQbWdodHRwOi8viOw']http://img[/URL]", $data[1]);
 $data = explode("', '", $data[0]);
 foreach($data as $i => $mp4)
 {
 if(strpos($mp4, '/videos/mp4/'))
 $list .= 'ลิงก์เสริม 360P=>'.trim($mp4).'|';
 }
 return rtrim($list, '|');
}
Код (разметка):

DeltaKilo


Рег
01 Jan, 2011

Тем
79

Постов
199

Баллов
644
Тем
403,760
Комментарии
400,028
Опыт
2,418,908

Интересно